How do you simplify #(a ^ { 1/ 2} a ^ { - 2/ 3} ) ^ { 12}#?

Question

540 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-24T09:41:20

#a^-2#

the rules of powers we need are

#x^m xx x^n=x^(m+n)#

#(x^m)^n=x^(mn),AAx,m,ninRR#

so we have

#(a^(1/2)a^(-2/3))^12#

#=(a^(1/2-2/3))^12#

#=(a^(-1/6))^12=a^(-1/6 xx 12)#

#=a^-2#