How do you simplify $abs(0.2 + 0.8i)$ ?

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Answer 1 · 2016-02-09T13:32:23

$|0.2+0.8i|=sqrt(0.68)=0.82621...$

The modulus of a complex number $a+bi$ , denoted $|a+bi|$ , is $sqrt(a^2+b^2)$

Then, in this case,

$|0.2+0.8i|=sqrt(0.2^2+0.8^2)$

$=sqrt(0.04+0.64)$

$=sqrt(0.68)$

$=0.824621...$

How do you simplify abs(0.2 + 0.8i)abs(0.2 + 0.8i)?