How do you simplify $abs(20 + 21i )$ ?

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Answer 1 · 2015-12-06T22:44:04

$abs(20+21i) = 29$

Using Pythagoras Theorem,

$abs(a+bi) = sqrt(a^2+b^2)$

So in our case:

$abs(20+21i) = sqrt(20^2+21^2) = sqrt(400+441) = sqrt(841) = 29$

How do you simplify abs(20 + 21i )abs(20 + 21i )?