# How do you simplify c^3v^9c^-1c^0?

Terms that have exponentials and the same base can have their exponentials added together, to get to
${c}^{2} {v}^{9}$

#### Explanation:

I'm assuming we are answering the question asked (with the c and v terms). In case the v was meant to be a c, I'll do that next.

${c}^{3} {v}^{9} {c}^{-} 1 {c}^{0}$

We can take terms with the same base and add their exponents together, like this:

${c}^{3 - 1 + 0} {v}^{9}$

${c}^{2} {v}^{9}$

In case all the terms are meant to be c terms, it'd look like:

${c}^{3 + 9 - 1 + 0}$

${c}^{11}$