How do you simplify #cos4theta-6sin2theta# to trigonometric functions of a unit #theta#?

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Answer 1 · 2018-06-07T04:13:49

f(t) = cos 4t - 6sin 2t
#cos 4t = 1 - 2sin^2 2t = 1 - 8sin^2 t.cos^2 t#
6sin 2t = 12sint.cos t
Finally,
#f(t) = 1 - 8sin^2 t.cos^2 t - 12sin t.cos t#