How do you simplify e^3lnx^5+4lny^2?

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Answer 1 · 2018-04-12T12:54:20

$x^6+8ln(y)$

By the laws of logarithms:

$a^(log_a(b))=b$

$log_a(b^c)=clog_a(b)$

$e^(3ln(x^2)+4ln(y^2)$

Rewriting:

$(e^(ln(x^2)))^3+8ln(y)$

$(x^2)^3+8ln(y)$

$x^6+8ln(y)$