Question

How do you simplify `\frac { 16x ^ { \frac { 1} { 3} } y ^ { 2} } { ( 8x ^ { 3} ) ^ { 1/ 3} }`?

Answer 1

`8 root[3]{x}/xy^2 = 8 x^(-2/3)y^2`

Explanation:

`frac{16x^(1/3)y^2}{8^(1/3) x} = frac{16}{2} * x^(1/3 - 1) * y^2`