How do you simplify #\frac { 24f ^ { 3} g ^ { 4} } { 16g ^ { 3} }#?

1 Answer
EZ as pi
Oct 18, 2016

#(3f^3g)/2#

Explanation:

#\frac { 24f ^ { 3} g ^ { 4} } { 16g ^ { 3} }#?

In algebraic fractions like these which have one term in both the numerator and denominator, the process is:

Simplify the numbers and subtract the indices of like bases.

#(cancel24^3f^3g^4)/(cancel16^2g^3)" "larr# HCF = 8

=#(3f^3g)/2#

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