How do you simplify #\frac { 2r ^ { 5} y ^ { 9} } { 3r ^ { 2} y ^ { 4} }#?

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Answer 1 · 2017-09-19T03:21:04

See a solution process below:

First, rewrite as:

#2/3(r^5/r^2)(y^9/y^4)#

Now, use this rule of exponents to simplify the #r# and #y# terms:

#x^color(red)(a)/x^color(blue)(b) = x^(color(red)(a)-color(blue)(b))#

#2/3(r^color(red)(5)/r^color(blue)(2))(y^color(red)(9)/y^color(blue)(4)) =>#

#2/3r^(color(red)(5)-color(blue)(2))y^(color(red)(9)-color(blue)(4)) =>#

#2/3r^3y^5#

Or

#(2r^3y^5)/3#