How do you simplify #\frac { 2x ^ { 2} y ^ { - 3} } { 2^ { 2} x ^ { - 1} y } #?
1 Answer
Mar 25, 2017
#=(x^3 )/( 2y^4#
Explanation:
Given -
#=(2x^2 y^(-3))/(2^2x^(-1) y)#
#=(x^2.x^1 )/( 2^2 . 2^(-1)y.y^3)#
#=(x^(2+1) )/( 2^(2-1)y^(1+3)#
#=(x^3 )/( 2y^4#
