How do you simplify #\frac { ( 3x ) ^ { - 2} } { ( 2x ) ^ { - 1} }# ?

1 Answer
Jul 29, 2018

#2/(9x)#

Explanation:

Recall that #x^(-a)/x^(-b)=x^b/x^a#. With this in mind, we can simply invert this fraction with positive exponents to get

#(2x)/(3x)^2#, or #(2x)/(9x^2)#, or, cancelling out a #x# in the numerator and denominator, we get

#2/(9x)#

Hope this helps!