Question

How do you simplify `\frac { ( 3x ^ { 2} y ^ { - 5} ) ^ { 4} } { ( 2x ^ { - 6} y ^ { 3} ) ^ { 2} }`?

Answer 1

`(81x^20)/(4y^26)`

Explanation:

`(3x^2y^-5)^4/(2x^-6y^3)^2= (3^4x^8y^-20)/(2^2x^-12y^6)`

`=81/4(x^(8-(-12))y^(-20-6)) =81/4x^20y^-26`

`=(81x^20)/(4y^26)` [Ans]