Question

How do you simplify `\frac { ( 4- 3i ) ( 4+ 3i ) } { 3- 4i }`?

Answer 1

`19/(3-4i)`

Explanation:

`((4-3i)(4+3i))/(3-4i)=(16-3i^2)/(3-4i)`
`(16+3)/(3-4i)` as (`i^2=-1`)
`=19/(3-4i)`