Question

How do you simplify `(\frac { 45x ^ { 4} y ^ { 3} } { 5x ^ { 8} y ^ { - 1} } ) ^ { \frac { 1} { 2} }`?

Answer 1

`+- (3y^2)/x^2`

Explanation:

`((45x^4y^3)/(5x^8y^(-1)))^(1/2)`

`= sqrt((45x^4y^3)/(5x^8y^(-1)))`

`= sqrt((9y^4)/(x^4))= +- (3y^2)/x^2`

`= +- (3y^2)/x^2` [Ans]