How do you simplify #\frac { 49a ^ { - 1} b ^ { - 3} } { 7a b ^ { 3} }#?

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Answer 1 · 2016-11-27T18:36:38

#7/(a^2b^6)#

First, rewrite as:

#49/7 a^-1/a b^-3/b^3#

#49/7 a^-1/a^1 b^-3/b^3#

Then using the rules for exponents and division simplify to:

#7 a^(-1 - 1) b^(-3 - 3) =>#

#7a^-2b^-6 =>#

#7/(a^2b^6)#