How do you simplify #\frac { ( 4v ^ { 3} ) ^ { 3} } { 6v ^ { 3} \cdot v ^ { 2} \cdot 5v }#?

1 Answer
James
May 15, 2018

#[64v^9]/[30*v^6 ]=64/30*v^3=32/15*v^3#

Explanation:

show below

#( 4v ^ { 3} ) ^ { 3}/[6v ^ { 3}*v ^ { 2} *5v ]#

#[(4v^3)^2*(4v^3)]/[6v^{ 3}*v^{ 2}*5v ]#

#[16v^6*(4v^3)]/[30*v^6 ]#

#[64v^9]/[30*v^6 ]=64/30*v^3=32/15*v^3#

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