How do you simplify #\frac{72ab^2c^{3}}{862c^{2}}#?

1 Answer
EZ as pi
Sep 30, 2016

#= (36ab^2c)/431#

Explanation:

Approach any fraction in this from in exactly the same way.
#rarr# Work with the signs - all positive in this case.
#rarr# simplify the numbers - both are even, #div 2#
#rarr# subtract the indices of like bases - only #c# in this case

#(72ab^2c^3)/(862c^2)" "larr (cancelc xx cancelc xx c)/(cancelc xx cancelc)#

#= (36ab^2c)/431" "larr# simplified as far as it can go!

Don't get put off by the big numbers!

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