How do you simplify #\frac { 8( 3u + 4) ( u - 8) } { 48( 3u + 4) ( u - 8) #?

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Answer 1 · 2017-09-27T15:24:10

See below.

#(8(3u+4)(u-8))/(48(3u+4(u-8))#

We can simplify this by cancelling factors which are common to both numerator and denominator.

So we have the common factors:

#(8cancel((3u+4))(u-8))/(48cancel((3u+4))(u-8))#

And:

#(8(3u+4)cancel((u-8)))/(48(3u+4)cancel((u-8)))#

Which gives us:

#(8cancel((3u+4))cancel((u-8)))/(48cancel((3u+4))cancel((u-8))) = 8/48#

HCF of #8/48# is #8#

So: #8/48=color(blue)(1/6)#