# How do you simplify \frac{a^{-2}b^{-3}}{c^{-1}} without any negative or fractional exponents in the answer?

Well, I am not completely sure it is what you want but here it is: $\frac{c}{{a}^{2} {b}^{3}}$
${a}^{- 2}$ it can go "downstairs" to the denominator loosing the minus sign: $\frac{1}{{a}^{2}}$;
Same thing with ${b}^{- 3}$ that becomes: $\frac{1}{{b}^{3}}$;
1/(c^(-1) becomes: ${c}^{1} = c$.