How do you simplify #\frac { b ^ { 2} c ^ { 8} } { b c ^ { 0} \cdot b ^ { - 1} c ^ { 7} }#?

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Answer 1 · 2018-01-23T06:20:59

#color(blue)(b^2c#

Given:

#(b^2*c^8)/(b*c^0*b^(-1)*c^7)#

#rArr (b^2*c^7*c^1)/(b*1*(1/b)*c^7)#

#rArr (b^2*c^7*c^1)/(b*1/b*c^7)#

#rArr (b^2*cancel c^7*c^1)/(cancel b*1/ cancel b*cancel c^7)#

#rArr (b^2*c)/1#

Hence the answer is

#color(blue)(b^2c)#