How do you simplify #\frac { \frac { 7} { 3} + \frac { 8} { 6} } { \frac { 3} { 11} - \frac { 1} { 22} }#?

3 Answers
Mar 27, 2017

Please see the explanation.

Explanation:

Multiply by 1 in the form of #2/2#

#(2(7/3+8/6))/(2(3/11-1/22) )= (14/3+8/3)/(6/11-1/11)#

Now that there are common denominators, we can combine the fractions:

#(14/3+8/3)/(6/11-1/11) = (22/3)/(5/11)#

We know that dividing by a fraction is the same thing as inverting (flipping) the divisor and multiplying:

#(22/3)/(5/11) = (22/3)(11/5)#

When you multiply two fractions, multiply the numerators and the denominators.

#(22/3)(11/5) = 242/15#

Mar 28, 2017

#242/15= 16 2/15#

Explanation:

Although it is possible to work with this fraction in this form, it is pretty daunting, so let's work with it in a simpler form:

#(7/3+8/6)" " div" " (3/11-1/22)" "larr# simplify each bracket

#((14+8)/6)" " div" "((6-1)/22)" "larr# change each bracket to LCD

#22/6color(white)(......) divcolor(white)(......) 5/22#

To divide fractions, multiply by the reciprocal of the second fraction

#22/6color(white)(......) xx color(white)(......) 22/5" "larr# cancel if possible (cancel by #2#)

#22/cancel6_3color(white)(......) xx color(white)(......) cancel22^11/5#

#=242/15#

#= 16 2/15#

Mar 29, 2017

#color(red)(16 2/15#

Explanation:

#(7/3+8/6)/(3/11-1/22)#

#:.=((14+8)/6)/((6-1)/22)#

#:.=(22/6)/(5/22)#

#:.=cancel22^color(red)11/cancel6^color(red)3 xx 22/5#

#:.=(11 xx22)/(3 xx 5)#

#:.=242/15#

#:.color(red)(=16 2/15#