How do you simplify #\frac { x ^ { 2} \cdot 4x ^ { 3} } { 6x }#?

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Answer 1 · 2016-12-07T23:36:01

#(2x^4)/3#

First, using the rules for exponents (#color(red)(x^a*x^b = x^(a+b))#) combine the terms in the numerator of the problem.

#(4x^(2+3))/(6x)#

#(4x^5)/(6x)#

Now we can pull out factors common to the numerator and denominator:

#(2x)/(2x) (2x^4)/3#

#cancel((2x))/cancel((2x)) (2x^4)/3#

#(2x^4)/3#