# How do you simplify \frac{x-2}{x^2-4x+4}?

First of all, you observe that the denominator ${x}^{2} - 4 x + 4$ is equal to ${\left(x - 2\right)}^{2}$, and so you rewrite your fraction as
$\setminus \frac{x - 2}{{\left(x - 2\right)}^{2}} = \setminus \frac{1}{x - 2}$.
This means that the fraction can be written only if $x \setminus \ne 2$