How do you simplify #\frac { ( - x ^ { 4} y ^ { 0} ) ^ { 0} } { - x ^ { 4} y ^ { - 2} \cdot - y ^ { 4} }#?
1 Answer
Dec 18, 2017
#1/(x^4y^2)#
Explanation:
Given -
#=((-x^4y^0)^0)/(-x^4y^(-2).-y^4)#
Any value raised to power zero is equal to one. Hence -
#=1/(-x^4y^(-2)xx(-y^4)#
#1/(x^4y^(-2+4)#
#1/(x^4y^2)#
