How do you simplify #ln e^2#?

1 Answer
Apr 27, 2018

Answer:

2

Explanation:

#ln(x)# is asking #e# to the power of what is #x#

In this case, #e# to the power of #2# is #e^2#

thus, #ln(e^2)=2#

Another way is using the property of logarithms that says #ln(a^b)=b*ln(a)#

In this case, #a=e# and #b=2#
Thus, #ln(e^2)=2*ln(e)=2*1=2#