How do you simplify #lne^4#?

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9
Feb 22, 2016

Answer:

#4#

Explanation:

You may put any power in the argument before the #ln#:
#lne^4=4lne# (this goes for #log#'s to any base)

Then since #e# is the base of the #ln#-function (#lnx=log_e x#), it follows that: #lne=log_e e=1#, just as #log_10 10=1#

So: #lne^4=4*lne=4*1=4#

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