Question

How do you simplify `log_2(2^x)`?

Answer 1

`log_2(2^x) = x`

Explanation:

The logarithm `log_b` for any (meaningful) base `b` is the inverse of the exponent using that base.

So `log_b(b^x) = x` for any Real number `x` and base `b > 0` with `b != 1`