How do you simplify #log_8 16 + log_8 256#?

1 Answer
Jun 20, 2016

Answer:

Giving approximate answer of #4.004# to 3 decimal places as a value

Simplified form#->log_8(4128)#

Explanation:

The addition of logs represents multiplication of the source numbers

#log_8(16)+log_8(256)" " =" " log_8(16xx258)" "=" "log_8(4128)#

Converting log base 8 to log base 10

#log_10(4128)/log_10(8) ~~4.0037#

Giving approximate answer of #4.004# to 3 decimal places