How do you simplify #log_ax - log_a9 - log_a(x^2+1) + log_a5#?
1 Answer
Apr 23, 2016
Explanation:
Using the following
#color(blue)" laws of logarithms " #
#• logx + logy hArr log(xy)#
#• logx - logy hArr log(x/y) # rewriting the above expression as follows:
# log_a x + log_a 5 -(log_a 9 + log_a(x^2+1))#
#rArr log_a(5x) - ( log_a (9(x^2+1))#
# = log_a ((5x)/(9(x^2+1)))#