Question

How do you simplify `\log ( \frac { a ^ { 2} } { b c } ) + \log ( \frac { b ^ { 2} } { a c } ) + \log ( c^2/(ab))`?

Answer 1

`0`

Explanation:

another approach is to use the law

`logX+logY=log(XY)`

`log(a^2/(bc))+log(b^2/(ac))+log(c^2/(ab))`

`=log((a^2b^2c^2)/(bcacab))`

`=log((a^2b^2c^2)/(a^2b^2c^2))`

`=log1=0`