How do you simplify #log (x+6)=1-log(x-5)#?
I tried this:
We can use, as an example, the base of the logs as being
use a property of logs to write:
use the definition of log to write:
the negative solution cannot be accepted.
Condense the Left Side into 1 Log expression
Convert from Log Equation to Exponential Equation
Multiply Left Side
Since we can't factor, use Quadratic Formula:
Since the "inside" of log has to be positive,