How do you simplify #log x + log (x^2 - 196) - log 2 - log (x - 14)#?

1 Answer
Jun 1, 2018

Answer:

#log((x*(x^2-16))/(2*(x-14)))#

Explanation:

We write
#log(x)+log(x^2-16)-(log(2)+log(x-14))#
and this is
#log(x*(x^2-16))-log(2(x-14))#
This is
#log((x(x^2-16))/(2*(x-14)))#
We have used that
#log(ab)=log(a)+log(b)#
#log(a/b)=log(a)-log(b)#
for #a,b>0#