How do you simplify #log5(x + 4) -log5(x + 1)#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer GiĆ³ Sep 1, 2015 I got as far as: #log[(x+4)/(x+1)]# Explanation: I would use the fact that: #logx-logy=log(x/y)# to get: #log5(x+4)-log5(x+1)=log[(cancel(5)(x+4))/(cancel(5)(x+1))]=log[(x+4)/(x+1)]# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 2235 views around the world You can reuse this answer Creative Commons License