How do you simplify #logx^2-logxy+4logy#?

1 Answer
Jul 15, 2016

Answer:

#log ((x^2 y^4)/(xy))#

Explanation:

#logx^2-logxy+4logy#

3 log terms can be written as the log of a single term.

If logs are added, then the numbers are multiplied.
If logs are subtracted, then the numbers are divided.

#logx^2-logxy+4logy = logx^2-logxy+logy^4#

#log ((x^2 y^4)/(xy))#