How do you simplify #(m-2)/(m-5)*(m+5)/(m-2)#?

1 Answer
Jul 25, 2015

You cancel out the terms common to the nominator and to the denominator.


Notice that you initial expression has #(m-2)# as the numerator of the first fraction and as the denominator of the second fraction.

This means that you can cancel out this term to get

#cancel(m-2)/(m-5) * (m+5)/cancel(m-2) = color(green)((m+5)/(m-5))#

And that is how your simplified expression looks like.