How do you simplify #((n-1)!) /( n!) #?

1 Answer
Dec 3, 2015

Answer:

Answer: #1/n#

Explanation:

Factorial mean multiply the all the number by counting down...

#((n-1)!)/(n!) = [(n-1)(n-2)(n-3)!]/((n)(n-1)(n-2)(n-3)!#

# = [cancel((n-1)(n-2)(n-3)!)]/((n)cancel((n-1)(n-2)(n-3)!)#

= # 1/n#