How do you simplify (n^2-4)/(n^2-2n)*n/(n^2+10n+16)n24n22nnn2+10n+16?

1 Answer
Nov 9, 2016

1/(n+8)1n+8

Explanation:

(n^2-4)/(n^2-2n)xxn/(n^2+10n+16)n24n22n×nn2+10n+16

factorise where possible

((n+2)(n-2))/(n(n-2))xxn/((n+8)(n+2))(n+2)(n2)n(n2)×n(n+8)(n+2)

cancel where possible

((n+2)(n-2))/(cancel((n))(n-2))xxcancel(n)/((n+8)(n+2))

((n+2)cancel((n-2)))/cancel((n-2))xx/((n+8)(n+2))

cancel((n+2))xx1/((n+8)cancel((n+2)))

=1/(n+8)