How do you simplify #(n^2-4)/(n^2-2n)*n/(n^2+10n+16)#?

Question

1400 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-09T16:04:24

#1/(n+8)#

#(n^2-4)/(n^2-2n)xxn/(n^2+10n+16)#

factorise where possible

#((n+2)(n-2))/(n(n-2))xxn/((n+8)(n+2))#

cancel where possible

#((n+2)(n-2))/(cancel((n))(n-2))xxcancel(n)/((n+8)(n+2))#

#((n+2)cancel((n-2)))/cancel((n-2))xx/((n+8)(n+2))#

#cancel((n+2))xx1/((n+8)cancel((n+2)))#

#=1/(n+8)#