How do you simplify #((n+2)! )/( n!)#?

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

7
Mar 2, 2018

Answer:

#n^2+3n+2#

Explanation:

We can rewrite the numerator as:

#((n+2) * (n+2-1) * (n+2-2)!)/((n)!)#

#=((n+2) * (n+1) * (n)!)/((n)!)#

We can cancel #(n)!# and #(n)!# out:

#=((n+2) * (n+1) * 1)/1#

#=(n+2) * (n+1)#

#=n^2+3n+2#

Thus, solved

Was this helpful? Let the contributor know!
1500
Trending questions
Impact of this question
6626 views around the world
You can reuse this answer
Creative Commons License