How do you simplify $((n+2)!)/((n-1)!)$ ?

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Answer 1 · 2016-11-15T14:19:27

$((n+2)!)/((n-1)!) = ((n+2)(n+1)(n)(n-1)(n-2) ... 1)/((n-1)(n-2)...1)$
$:. ((n+2)!)/((n-1)!) = (n+2)(n+1)(n)$

How do you simplify ((n+2)!)/((n-1)!)((n+2)!)/((n-1)!)?