How do you simplify #(p^3n^-2)/(n^2p^4)#?

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Answer 1 · 2018-03-24T14:23:37

#=> p^(-1)n^(-4)#

or

#=>1/(pn^4)#

We start with:

#=>(p^3n^(-2))/(n^2p^4)#

We identify terms that are similar:

#=>(color(blue)(p^3)color(red)(n^(-2)))/(color(red)(n^2)color(blue)(p^4))#

Terms with powers that are divided can be rewritten in the numerator with the difference of the powers.

#=>color(blue)(p^(3-4))color(red)(n^(-2-2))#

#=> p^(-1)n^(-4)#

Rewriting without negative powers:

#=>1/(pn^4)#