How do you simplify #\root [ 3] { 2x ^ { 6} }#?

1 Answer
Feb 4, 2017

See the entire simplification process below:

Explanation:

First, use this rule for radicals and exponents to rewrite this expression: #root(color(red)(n))(x) = x^(1/color(red)(n))#

#root(color(red)(3))(2x^6) = (2x^6)^(1/color(red)(3))#

Now use these rules for exponents to further simplify:

#a = a^color(red)(1)# and #(x^color(red)(a))^color(blue)(b) = x^(color(red)(a) xx color(blue)(b))#

#(2x^color(red)(6))^(1/color(blue)(3)) = (2^color(red)(1)x^color(red)(6))^(1/color(blue)(3)) =2^(color(red)(1) xx color(blue)(1/3))x^(color(red)(6) xx color(blue)(1/3)) = 2^(1/3)x^(6/3) =#

#2^(1/3)x^2# or #root(3)(2)x^2# or #1.2599x^2# rounded to the nearest ten thousandth.