Question

How do you simplify `\root(5) (128x^7y^28)`?

Answer 1

`2xy^5\root[5]{4x^2y^3}`

Explanation:

`\root[5]{128x^7y^{28}}`

`=\root[5]{2^7x^7y^{28}}`

`=\root[5]{(2xy^5)^{5}2^2x^2y^{3}}`

`=\root[5]{(2xy^5)^{5}}\root[5]{2^2x^2y^{3}}`

`=2xy^5\root[5]{4x^2y^3}`