How do you simplify #root3 (x^6 y^7)/root3 9#?
You have the expression
Remember that the cubic root
("multiplied with itself three times" is, of course, not quite precise, but I mean that n is a factor three times, i.e.
Let's rewrite the expression a little:
Or if you will
depending on what you prefer.
We may be fooled to think that