How do you simplify #(root3y)+5(root3y)#?

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Answer 1 · 2018-04-21T05:18:45

#(root(3)y) + 5(root(3)y)=6(root(3)y)#

Simplify:

#(root(3)y) + 5(root(3)y)=#

#6(root(3)y)#

Answer 2 · 2018-04-21T06:03:08

#6root3(y)#

The first thing is to notice that there are two terms.
(There is a + sign between them.)

Then notice that the terms themselves are the same. That means they can be added.

If we had #2x + 7x# we would add and get #9x#
If no number is shown it means #1#.

#x+5x =6x#

In our case the terms are in #root3(y)#

To simplify, add the coefficients.

#1(root3(y))+5(root3(y))#

#=6(root3(y))#

The brackets are not necessary.