How do you simplify #root4((16a^4)^5)#?

1 Answer
EZ as pi
Sep 26, 2016

#32a^5#

Explanation:

Powers and roots are equally strong operations, so it does not matter which is done first.

However, raising to a power first gives VERY big values to work with, so I prefer to find the root first and then raise to the power.

Note: #2^4 = 16, " so " root4(16) = 2#

#color(red)((root4(16a^4)))^5 = color(red)((2a))^5#

#32a^5#

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