How do you simplify #secx/tanx#?

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Answer 1 · 2016-11-13T11:33:30

#cscx#

Use #tanx=sinx/cosx#

And #secx=1/cosx#

So,#secx/tanx=1/cosx*cosx/sinx=1/sinx=cscx#

Answer 2 · 2018-06-20T23:42:05

#secx/tanx=cscx#

Let's use the definitions of #secx# and #tanx# to simplify this. We know

#secx=1/cosx# and #tanx=sinx/cosx#. Let's plug these values into our original expression. we get

#(1/cosx)/(sinx/cosx)=(1/cancel(cosx))/(sinx/cancel(cosx))=>1/sinx=>cscx#

Therefore, #secx/tanx=cscx#

Hope this helps!