How do you simplify ${sin}^{2} (2 x) - {cos}^{2} (2 x)$ $sin^2(2x) - cos^2(2x)$ ?

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Answer 1 · 2016-07-08T16:00:57

$\Rightarrow - cos 4 x$ $=>-cos4x$

${sin}^{2} (2 x) - {cos}^{2} (2 x)$ $sin^2(2x) - cos^2(2x)$

$\Rightarrow - ({cos}^{2} (2 x) - {sin}^{2} (2 x))$ $=>-(cos^2(2x)-sin^2(2x) )$

$\Rightarrow - cos 4 x$ $=>-cos4x$

Applying identity ${cos}^{2} x - {sin}^{2} x = cos 2 x$ $cos^2x-sin^2x=cos2x$

How do you simplify sin2(2x)−cos2(2x)sin^2(2x) - cos^2(2x)?