How do you simplify #(sin^2theta-9)/(2costheta+1)*(10costheta+5)/(3sintheta+9)#?
1 Answer
Oct 15, 2016
Explanation:
Numeratot N = (sin t - 3)(sin t + 3) . 5(2cos t + 1)
Denominator D = (2cos t + 1) . 3(sin t + 3)
After simplication:
