Question

How do you simplify `[sin((pi/2)+h)-sin(pi/2)]/(h)`?

Answer 1

It is

`[sin((pi/2)+h)-sin(pi/2)]/(h)=[(sin(pi/2)cosh+cos(pi/2)*sinh)-sin(pi/2)]/[h]=(cosh-1)/[h]`

Note that

1.`sin(a+b)=sina*cosb+cosa*sinb`
2.`sin(pi/2)=1` , `cos(pi/2)=0`