How do you simplify #(sin(x) * cos (x))/(1-cos^2 (x))#?
1 Answer
Jun 7, 2016
Explanation:
Given,
#(sinxcosx)/(1-cos^2x)#
Replace
#=(sinxcosx)/(sin^2x)#
Cancel out
#=(sinxcosx)/(sinxsinx)#
#=(color(red)cancelcolor(black)sinxcosx)/(color(red)cancelcolor(black)sinxsinx)#
#=color(green)(|bar(ul(color(white)(a/a)color(black)((cosx)/(sinx))color(white)(a/a)|)))#